Find four consecutive integers whose sum is -2
Answers
Answered by
1
Let first integer be x
Second-x+1
Third-x+2
Fourth-x+3
On adding
x+x+1+x+2+x+3=-2
4x+6=-2
2(2x+3)=-2
2x+3=-1
2x=-4
x=-4/2
x=-2
Therefore integers are-
-2,-1,0,1
Hopefully that is correct.
Second-x+1
Third-x+2
Fourth-x+3
On adding
x+x+1+x+2+x+3=-2
4x+6=-2
2(2x+3)=-2
2x+3=-1
2x=-4
x=-4/2
x=-2
Therefore integers are-
-2,-1,0,1
Hopefully that is correct.
Answered by
2
Let the Four consecutive integers be
x, x+1, x+2 & x+3.
According to question:-
x + (x+1) + (x+2) + (x+3) = -2
4x +6 = -2
4x = -2-6
4x = -8
x = -8/4
x = -2
So the integers are,
x = -2,
x+1 = -2+1
= -1,
x+2 = -2+2
= 0 &
x+3 = -2+3
= 1
Hope it helps u.
x, x+1, x+2 & x+3.
According to question:-
x + (x+1) + (x+2) + (x+3) = -2
4x +6 = -2
4x = -2-6
4x = -8
x = -8/4
x = -2
So the integers are,
x = -2,
x+1 = -2+1
= -1,
x+2 = -2+2
= 0 &
x+3 = -2+3
= 1
Hope it helps u.
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