Question

• Find four consecutive integers whose sum is 238.

Answer 1

the four consecutive no. which sum gets 238 is 119/5; 129/5; 124/5; 139/5

Answer 2

Answer:

Let the four consecutive integers be x, x+1, x+2 and x+3.

ATQ.

x+x+1+x+2+x+3=238

4x+6=238

4x=232

x=58

Now, x=58

x+1=58+1=59

x+2=58+2=60

x+3=58+3=61

Therefore, the three consecutive integers are 58, 59, 60 and 61.