Question

find four consecutive integers with a sum of 106

Answer 1

Heya!!


Here's ur answer..


Let the numbers be x, x +1, x + 2, x + 3

So, according to the question :
x + x +1 + x + 2 + x +3 = 106
4x +6 = 106
4x = 100
x = 25.


Numbers are : 25, 26, 27, 28.


Hope it helps!!

Thank you ☺️

Answer 2

Answer:

25, 26, 27, and 28 are the required four consecutive integers.

Step-by-step explanation:

Step 1 of 2

According to the question,

The sum of $4$ consecutive integers is $106$.

Let the four consecutive integers be x, x + 1, x + 2 and x + 3.

Then,

x + (x + 1) + (x + 2) + (x + 3) = 106

x + x+ 1 + x + 2 + x + 3 = 106

Now, solve for x.

4x + 6 = 106

4x = 106 - 6

4x = 100

x = 100/4

x = 25

Step 2 of 2

The four consecutive integers are:

The first integer is x = 25.

The second integer is,

= x + 1

= 25 + 1

= 26

The third integer is,

= x + 2

= 25 + 2

= 27

The fourth integer is,

= x + 3

= 25 + 3

= 28

Final answer: 25, 26, 27, and 28 are the required four consecutive integers.

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