Find four consecutive integers with the sum of -142.
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Given:
Sum of four consecutive integers = - 142
To find :
The four consecutive integers whose sum is - 142.
Solution:
Let the four consecutive integers are,
n , n + 1 , n + 2 , n + 3
Sum of four consecutive integers = - 142
Therefore,
n + n + 1 + n + 2 + n + 3 = - 142
4n + 6 = - 142
4n = - 142 - 6
4n = - 148
n =
n = - 37
Thus, the four consecutive integers are,
-37 , (-37 ) + 1 , (-37 ) + 2 , (-37 ) + 3
- 37 , - 36 , - 35 , - 34
Final answer:
The four consecutive integers with the sum of - 142 are,
- 37 , - 36 , - 35 , - 34
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