Question

Find four consecutive multiples of 5 with a sum of 210.

Answer 1

Step-by-step explanation:

Let n = the first of three consecutive numbers.

Let n + 1 = the second consecutive number, and ...

Let n + 2 = the third consecutive number.

Since we're given that: "the sum of three consecutive numbers is 210," then we can now translate this statement mathematically into the following equation to be solved for the unknown number n:

n + (n + 1) + (n + 2) = 210

n + n + 1 + n + 2 = 210

Collecting like-terms on the left, we get:

3n + 3 = 210

3n + 3 - 3 = 210 - 3

3n + 0 = 207

3n = 207

(3n)/3 = 207/3

(3/3)n = 207/3

(1)n = 69

n = 69

Therefore, ,...

n + 1 = 69 + 1 = 70 and

n + 2 = 69 + 2 = 71

CHECK:

n + (n + 1) + (n + 2) = 210

69 + (70) + (71) = 210

69 + 70 + 71 = 210

210 = 210

Answer 2

Answer:

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Step-by-step explanation:

Any multiple of 5 can be written as 5x.

The next multiple will be when x increases by 1.

The sum of four consecutive multiples of 5 is 90.

5x+5(x+1)+5(x+2)+5(x+3)=90.

5x+5x+5+5x+10+5x+15=90.

20x+30=90.

20x=60.

x=3.