Math, asked by harshbhushan680, 9 months ago

Find four consecutive multiples of 7 whose sum is 238

Answers

Answered by aabritipradhan

1

Four consecutive multiples of 7 are-

49+56+63+70

=238

Answered by subhamsingh5318

1

Answer:

four consecutive multiples of 7 whose sum is 238 is 49+56+63+70

Step-by-step explanation:

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