Find four consecutive odd number whose sum is 24
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Answer:13,11
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Let the consecutive odd numbers=2n+1,2n+3,2n+5,2n+7
Given that
Sum of consecutive odd numbers=24
(2n+1)+(2n+3)+(2n+5)+(2n+7)=24
8n+16=24
8n=24-16
8n=8
n=8/8
n=1
four consecutive odd numbers =3,5,7,9
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