find four consecutive odd numbers such that three times largest number added to twice the smallest number 93 find the number
Answers
Answered by
2
Answer:
Step-by-step explanation:
Let the 4 consecutive nos. be x,x+1,x+3 and x+5
Three times the largest no. is added to twice the smallest no. = 3x+5+2x+x
According to the problem
3x+5+2x+x+x+3 = 93
=>8+7x = 93
=> 7x = 93-8
=> 7x = 85
=> x= 85/7
Answered by
5
Answer:
15,17,19,21
Step-by-step explanation:
consecutive odd numbers = 2x+1,2x+3,2x+5,2x+7
A to Q...
3(2x+7)+2(2x+1) = 93
6x+21+4x+2=93
10x+23=93
10x=70
x=7
2x+1=2(7)+1=15
2x+3=2(7)+3=17
2x+5=2(7)+5=19
2x+7=2(7)+7=21
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