Question

find four consecutive odd numbers such that three times largest number added to twice the smallest number 93 find the number​

Answer 1

Answer:

Step-by-step explanation:

Let the 4 consecutive nos. be x,x+1,x+3 and x+5

Three times the largest no. is added to twice the smallest no. = 3x+5+2x+x

According to the problem

3x+5+2x+x+x+3 = 93

=>8+7x = 93

=> 7x = 93-8

=> 7x = 85

=> x= 85/7

Answer 2

Answer:

15,17,19,21

Step-by-step explanation:

consecutive odd numbers = 2x+1,2x+3,2x+5,2x+7

A to Q...

3(2x+7)+2(2x+1) = 93

6x+21+4x+2=93

10x+23=93

10x=70

x=7

2x+1=2(7)+1=15

2x+3=2(7)+3=17

2x+5=2(7)+5=19

2x+7=2(7)+7=21

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