Find four consecutive odd numbers such that three times the largest number added to twice the smallest number is 93. Which of these are prime numbers?
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Step-by-step explanation:
let the four consecutive odd numbers be
x, x+2, x+4, x+6
according to the question,
3 (x+6 ) +2x =93
3x+18+2x=93
5x=93-18
5x=75
x=75/5=15
so the four odd consecutive numbers are
x=15
x+2=15+2=17
x+4=15+4=19
x+6=15+6=21
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