Question

find four consecutive odd numbers such that three times the largest number added to twice the smallest number is 93. which of these are prime numbers​

Answer 1

Answer:

15, 17, 19, 21

17 and 19 are prime number

Step-by-step explanation:

let the 4 consecutive odd numbers be x, x+2, x+4, x +6

three times the largest number + two times the smaller number is = 93

$3(x + 6) + 2(x) = 93 \\ 3x + 18 + 2x = 93 \\ 5x = 93 - 18 \\ 5x = 75 \\ x = \frac{75}{5} \\ x = 15$

the numbers are

x = 15

x + 2 = 15 + 2 = 17

x + 4 = 15 + 4 = 19

x + 6 = 15 + 6 = 21

17 and 19 are prime number

verification

3(21) + 2(15)

= 63 + 30

= 93

hope you get your answer