Find four consecutive odd numbers such that three times the largest number added to twice the smallest number is 93. Which of these are prime numbers?
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Step-by-step explanation:
Let the first number be x.
Therefore, the other numbers are: x+2, x+4, x+6.
According to the question,
3(x+6) +2(x) = 93
3x + 18 +2x = 93
5x = 93-18
5x = 75
x = 75/5
x = 15
The numbers are:
1st : 15
2nd : 15 + 2 = 17
3rd : 15 + 4 = 19
4th : 15 + 6 = 21
Therefore, The prime numbers are 17 and 19
Hope it helps
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