Find four consecutive term in A.P. whose sum is 20 and sum of 3rd and
4th term is 1.
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Step-by-step explanation:
a-3d+a-d+a+d+a+3d=20
4a=20
a=5
a+2d+a+3d=1
5+5+5d=1
5d=-9
d=-9/5
So the terms after substitution of a & b are:
-2/5,16/5,34/5,52/5
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