Question

find four consecutive term in an A.P. Whose sum is 36 and the product of the 2nd and the 4th is 150. the term are in ascending order.
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Answer 1

Answer:

12,10,8,6

Step-by-step explanation:

Step-by-step explanation:S

Step-by-step explanation:S 4

Step-by-step explanation:S 4

Step-by-step explanation:S 4 =36

Step-by-step explanation:S 4 =36⇒

Step-by-step explanation:S 4 =36⇒ 2

Step-by-step explanation:S 4 =36⇒ 24

Step-by-step explanation:S 4 =36⇒ 24

Step-by-step explanation:S 4 =36⇒ 24 [2a+(4−1)d]=36

Step-by-step explanation:S 4 =36⇒ 24 [2a+(4−1)d]=36⇒2a+3d=18⟶(1)

Step-by-step explanation:S 4 =36⇒ 24 [2a+(4−1)d]=36⇒2a+3d=18⟶(1)A/Q,a

Step-by-step explanation:S 4 =36⇒ 24 [2a+(4−1)d]=36⇒2a+3d=18⟶(1)A/Q,a 2

Step-by-step explanation:S 4 =36⇒ 24 [2a+(4−1)d]=36⇒2a+3d=18⟶(1)A/Q,a 2

Step-by-step explanation:S 4 =36⇒ 24 [2a+(4−1)d]=36⇒2a+3d=18⟶(1)A/Q,a 2 .a

Step-by-step explanation:S 4 =36⇒ 24 [2a+(4−1)d]=36⇒2a+3d=18⟶(1)A/Q,a 2 .a 3

Step-by-step explanation:S 4 =36⇒ 24 [2a+(4−1)d]=36⇒2a+3d=18⟶(1)A/Q,a 2 .a 3

Step-by-step explanation:S 4 =36⇒ 24 [2a+(4−1)d]=36⇒2a+3d=18⟶(1)A/Q,a 2 .a 3 =a

Step-by-step explanation:S 4 =36⇒ 24 [2a+(4−1)d]=36⇒2a+3d=18⟶(1)A/Q,a 2 .a 3 =a 1

Step-by-step explanation:S 4 =36⇒ 24 [2a+(4−1)d]=36⇒2a+3d=18⟶(1)A/Q,a 2 .a 3 =a 1

Step-by-step explanation:S 4 =36⇒ 24 [2a+(4−1)d]=36⇒2a+3d=18⟶(1)A/Q,a 2 .a 3 =a 1 .a

Step-by-step explanation:S 4 =36⇒ 24 [2a+(4−1)d]=36⇒2a+3d=18⟶(1)A/Q,a 2 .a 3 =a 1 .a 4

Step-by-step explanation:S 4 =36⇒ 24 [2a+(4−1)d]=36⇒2a+3d=18⟶(1)A/Q,a 2 .a 3 =a 1 .a 4

Step-by-step explanation:S 4 =36⇒ 24 [2a+(4−1)d]=36⇒2a+3d=18⟶(1)A/Q,a 2 .a 3 =a 1 .a 4 +8

Step-by-step explanation:S 4 =36⇒ 24 [2a+(4−1)d]=36⇒2a+3d=18⟶(1)A/Q,a 2 .a 3 =a 1 .a 4 +8⇒(a+d)(a+2d)=a.(a+3d)+8

Step-by-step explanation:S 4 =36⇒ 24 [2a+(4−1)d]=36⇒2a+3d=18⟶(1)A/Q,a 2 .a 3 =a 1 .a 4 +8⇒(a+d)(a+2d)=a.(a+3d)+8⇒d

Step-by-step explanation:S 4 =36⇒ 24 [2a+(4−1)d]=36⇒2a+3d=18⟶(1)A/Q,a 2 .a 3 =a 1 .a 4 +8⇒(a+d)(a+2d)=a.(a+3d)+8⇒d 2

Step-by-step explanation:S 4 =36⇒ 24 [2a+(4−1)d]=36⇒2a+3d=18⟶(1)A/Q,a 2 .a 3 =a 1 .a 4 +8⇒(a+d)(a+2d)=a.(a+3d)+8⇒d 2 =4

Step-by-step explanation:S 4 =36⇒ 24 [2a+(4−1)d]=36⇒2a+3d=18⟶(1)A/Q,a 2 .a 3 =a 1 .a 4 +8⇒(a+d)(a+2d)=a.(a+3d)+8⇒d 2 =4⇒d=±2

Step-by-step explanation:S 4 =36⇒ 24 [2a+(4−1)d]=36⇒2a+3d=18⟶(1)A/Q,a 2 .a 3 =a 1 .a 4 +8⇒(a+d)(a+2d)=a.(a+3d)+8⇒d 2 =4⇒d=±2If d=2 then a=6

Step-by-step explanation:S 4 =36⇒ 24 [2a+(4−1)d]=36⇒2a+3d=18⟶(1)A/Q,a 2 .a 3 =a 1 .a 4 +8⇒(a+d)(a+2d)=a.(a+3d)+8⇒d 2 =4⇒d=±2If d=2 then a=6then the four terms is 6,8,10,12

Step-by-step explanation:S 4 =36⇒ 24 [2a+(4−1)d]=36⇒2a+3d=18⟶(1)A/Q,a 2 .a 3 =a 1 .a 4 +8⇒(a+d)(a+2d)=a.(a+3d)+8⇒d 2 =4⇒d=±2If d=2 then a=6then the four terms is 6,8,10,12If d=−2 then a=12

Step-by-step explanation:S 4 =36⇒ 24 [2a+(4−1)d]=36⇒2a+3d=18⟶(1)A/Q,a 2 .a 3 =a 1 .a 4 +8⇒(a+d)(a+2d)=a.(a+3d)+8⇒d 2 =4⇒d=±2If d=2 then a=6then the four terms is 6,8,10,12If d=−2 then a=12then the four terms is 12,10,8,6