Question

find four consecutive term is an A.P, whose sum is 36 and product of the 2nd and 4th is 105.

Answer 1

Given :-

find four consecutive term is an A.P, whose sum is 36 and product of the 2nd and 4th is 105.

To Find :-

To find the 2nd and 4th is 105.

Solution:-

Let the 4 terms be a-3d, a-d, a+d, and a+3d

Sum = 4a=36, so a= 9

Product of 2nd and 4th = (9-d) (9+3d) =105

81+27d-9d-3d2=105

3d2-18d+24=0

d2-6d+8=0

(d-2) (d-4) =0

So d=2, or 4

Number are

3, 7, 11, 15

Or

-3, 5,13,213,

Answer:-

3, 7, 11, 15

Or

-3, 5,13,213,