find four consecutive terms in A.P such that the sum of middle two terms is 18 and the product of the two end terms is 45
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a-3d, a+d , a-d , a+3d.given the sum of the middle terms is 18.
2a = 18
a = 9
(a-3d)2 = 45a² - 9d² = 45
9² - 9d² = 45
81 - 9d² = 45
9d² = 81 - 45
9d² = 36
d = 2 or -2
Putting a = 9 and d = -2 or 2 we get four terms 3, 7, 11 and 15plz mark as brainliest
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