Question

* Find four consecutive terms in an A.P. whose sum is 12 and sum of 3rd and 4th term
is 14.
(Assume the four consecutive terms in A.P. are a -d, a, a + d, a + 2d.)​

Answer 1

Answer:

-3,1,5,9

Step-by-step explanation:

2a+3d = 14

4a+2d=12 which implies 2a+d=6

Solving

2d = 8

d = 4.

Therefore a= 1.

So series is -3,1,5,9