Find four consecutive terms in an A.P. whose sum is 12 and sum of
3rd and 4th term is 14.
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Assume that the four consecutive terms in A.P. are a – d, a, a + d, a +2d .
It is given that,
Sum of four consecutive terms = 12
Sum of 3rd and 4th term = 14
Hence, the terms are –3, 1, 5 and 9.
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