Question

find four consecutive terms in an a.p whose sum is 12 and sum of 3rd and 4th is 14 ( assume the four consecutive terms in a.p are a- d , a, a+ d , a+2d​

Answer 1

Answer:

-3,1,5,9 hope it helps u

Step-by-step explanation:

a-d+a+a+d+a+2d = 12

4a+ 2d = 12

2a+ d= 6 _____1)

a+d + a+ 2d = 14

2a + 3d = 14 ______2)

solving 1) and 2) we get;

a= 1 and d= 4

then

1st term = a-d = 1-4= -3

2nd = a = 1

3rd = a+d = 1+4 = 5

4th = a+ 2d = 9