Question

Find four consecutive terms in an A.P. whose sum is 12 and sum of 2nd and 4th terms is 10​

Answer 1

Answer:

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Step-by-step explanation:

ATQ a+a+d+a+2d+a+3d=12=>4a+6d=12=>2a+3d=12--(1)

also, a+d +a+3d =10=>2a+4d=10--(2)

(1)-(2) gives -d=2=> d=-2

put in (1),we get a= 9

Required terms are 9,7,5,3