Question

Find four consecutive terms in an A.P. whose sum is 36 and the product of the 2n
and the 4th is 105. The terms are in ascending order. answer
​

Answer 1

Step-by-step explanation:

Let a-2d,a-d,a,a+d,a+2d be the AP

a-2d + a-d + a+d + a+2d = 36

=> 4a = 36

=> a = 9

(a-d)(a+2d) = 105

=> (9-d)(9+2d) = 105

=> 9(9+2d) - d(9+2d) = 105

=> 81 + 18d - 9d - 2d^2 = 105

Solve on ur own from here