Find four consecutive terms in an A.P. whose sum is 36 and the product of the 2n
and the 4th is 105. The terms are in ascending order. answer
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Step-by-step explanation:
Let a-2d,a-d,a,a+d,a+2d be the AP
a-2d + a-d + a+d + a+2d = 36
=> 4a = 36
=> a = 9
(a-d)(a+2d) = 105
=> (9-d)(9+2d) = 105
=> 9(9+2d) - d(9+2d) = 105
=> 81 + 18d - 9d - 2d^2 = 105
Solve on ur own from here
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