Question

find four consecutive terms in an a.p. whose sum is -54 and the sum of the 1st and the 3rd terms is -30

Answer 1

Answer:

Hello there!

Step-by-step explanation:

a + (a+1) + (a+2) + (a+3) = -54

4a+6=-54

a= -15

3rd term = a+2 = -13

1st + 3rd = -28

Hope it helps!