Question

find four consecutive terms in an A. P whose sum is -8 and the sum of the third and fourth term is 8??
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Answer 1

Answer:

The seventh term of an AP is four times the second term. If the sum from the third to the sixth term is 100, what is the AP?

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Let the second term is a2 and seventh term is a7.

a2 = a + d and a7 = a+6d

a7 = 4 a2

a+6d = 4(a+d)

a +6d = 4a +4d

3a = 2d

d = 3a/2

given that sum of 4 terms is 100

s = n/2(a + l)

100= 4/2( a3 + a6)

100=2( a+2d + a+5d)

50= 2a+7d

50 = 2a+7*3a/2

50= 2a +21a/2

100= 4a+21a

100= 25a

a= 100/25 =4

so, first term a = 4.

common difference d = 3*4/2=6

so, A.p. 4,10,16,22,28,34,40,46,……

Step-by-step explanation:

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