find four consecutive terms in an A.P.whose sum is 88 and the sum of the 1st and the 3rd terms is 40.
Answers
Answer:
Step-by-step explanation:
term is 40
Ask for details FollowReport by Riyasign 13.11.2018
Answers
THE BRAINLIEST ANSWER!
mysticd
Mysticd Maths AryaBhatta
Solution :
Let a , d are first term and common
difference of an A.P
Now ,
a , a+d , a+2d, a + 3d are first four
consecutive terms in A.P
Sum of 4 terms = 88 ( given )
=> a+a+d+a+2d+a+3d =88
=> 4a+6d = 88
Divide each term with 2 , we get
=> 2a + 3d = 44 ----( 1 )
Sum of first and 3rd term = 40(given )
=> a + a + 2d = 40
=> 2a + 2d = 40 ---( 2 )
subtract ( 2 ) from ( 1 ) , we get
d = 4
substitute d = 4 in equation (2),
we get
2a + 2×4 = 40
=> 2a = 40 - 8
=> 2a = 32
=> a = 32/2
=> a = 16
Therefore ,
a = 16 , d = 4
Required 4 terms are ,
a = 16 ,
a + d = 16 + 4 = 20 ,
a+2d = 16+2×4 = 24 ,
a+3d = 16+3×4 = 28
Please mark me as brainliest