Question

Find four consecutive terms in an AP .whose some is 12 and sum of 3rd and 4th term is 14

Answer 1

let our 4 consecutive term be... a-3d,a-d,a+d,and a+ 3d
so,, according to question,,,
a-3d+a-d+a+Da+3d=12
4a=12
so,a=3
now,,,t3+t4=14
so, a+2d+a+3d=14
2a+5d=14
2x3+5d=14
6+5d=14
d=8/5 and put the value of a and d u get four consecutive term that is a-3d,a-d,a+da+3d ansss