Question

Find four consecutive terms in an ap whose sum is 32and the sum of 1st and 3rd term is

Answer 1

6 and 7 and 8 and 9
6+8=14

Answer 2

Step-by-step explanation:

L et the terms be a-3d, a-d, a+d and a+3d

sum= a-3d+a-d+a+d + a+3d =32

4a = 32

a = 8

a+3d+ a+d = 24

2a+4d = 24

2×8 +4d = 24

16+ 4d = 24

4 d = 24 - 16

4d = 8

d= 2

terms are

8 -3×2, 8-2, 8+2, 8+3×2

2, 6, 10, 14

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