Question

Find four consecutive terms in an ap whose sum is 88 and the sum of first and the third term is 40

Answer 1

Answer: 16 , 20 , 24 , 28

Step-by-step explanation:

let the terms be (a-3d), (a-d), (a+d) and (a+3d)

sum = 88 = a-3d+a-d+a+d+a+3d ⇒ 4a = 88

= a = 22

a-3d + a+d = 40

= 2a-2d = 40

= a-d = 20

= 22-d = 20 ⇒ d = 2

numbers = (22-6)(22-2)(22+2)(22+6) = 16 , 20 , 24 , 28

Pls mark as Brainliest