Question

Find four consecutive terms in AP whose
Sum is 20 and sum of whose
Sum of whale Square is
120.​

Answer 1

Answer:

Given that sum of 4 consecutive terms in A.P is 20. Sum of whose squares is 120. ⇒ (a - 3d)2 + (a - d)2 + (a + d)2 + (a + 3d)2 = 120. ⇒ (5 - 3d)2 + (5 - d)2 + (5 + d)2 + (5 + 3d)2 = 120.

Answer 2

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Find four consecutive terms in AP whose Sum is 20 and sum of whose Sum of whale Square is

120.

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Give that sum of 4 consecutive terms in AP is 20 . sum of whose square is 120 .

=> (a-3d)2 + (a-d)2 + (a+d)2 + (a+3d)2 = 120 .

=> (5-3d)2 + (5-d)2 + (5+d)2 + (5+3d)2 = 120 .