Question

find four consecutive terms in AP whose sum is -54 and the sum of the first and third term is minus 30​

Answer 1

Answer:

Step-by-step explanation:

Sum of 4 terms - 4/2(2a+(4-1)d)=-54

2(2a+3d)=-54

2a+3d=-27

Sum of 1st and 3rd term = -30

2a+3d=-27

(-)2a+2d=-30 ->1

By eliminating we get d=3

And substituting d in 1

We get a=-18

A.P. : -18, -15, -12, -9