Question

find four consecutive terms of an arithmetic sequence whose sums of the terms is 130

Answer 1

Step-by-step explanation:

Let the 4 consecutive integers are x, x+1, x+2, x+3. It is given that the sum of 4 consecutive integers is 130. ... So, 4 consecutive integers are 31, 32, 33, 34.

Answer 2

The 4 consecutive terms are 31, 32, 33 and 34  

Given:

Sums of the four consecutive terms of an Arithmetic Sequence = 130

To find:

Find four consecutive terms

Solution:

Let x, x+1, x+2 and x+3 be the first term 4 consecutive terms of an Arithmetic Sequence with common difference 1

Sum 4 consecutive terms = x+x+1+x+2+x+3 = 4x+ 6

From given data sum of the 4 terms = 130

⇒ 4x+ 6 = 130

⇒ 4x = 124

⇒ x = 31

Therefore, the 4 consecutive terms are

31, 32, 33 and 34  

#SPJ2