Question

find four consecutive trems in an A.P. whose sum is 12 and the sum of the 3 and 4 term 14.

Answer 1

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Answer 2

Let the terms be a-d, a,a+d,a+2d
sum=4a+2d=12
2a+d=6......(1)
sum of 3rd and 4th =(a+d)+(a+2d)=14
2a+3d=14............(2)
subtract (1)-(2)
-2d=-8
d=4
from (1)
a=1
terms are
(1-4),1,(1+4),(1+2(4))
-3, 1, 5, 9

hope this helps you