Question

Find four consecutive tsuerms in an A.P. whose sum is 12 and the product of 3 rd and 4 th term is 45​

Answer 1

Answer:

let the terms be a-d, a,a+d,a+2d

sum=4a+2d=12

2a+d=6......(1)

sum of 3rd and 4th =(a+d)+(a+2d)=14

2a+3d=14............(2)

subtract (1)-(2)

-2d=-8

d=4

from (1)

a=1

terms are

(1-4),1,(1+4),(1+2(4))

-3, 1, 5, 9

Answer 2

Step-by-step explanation:

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