Question

Find four conservative terms in an a.p whose sum is -54and the sum of 1st 3rd term is -30?

Answer 1

Step-by-step explanation:

Let four consecutive terms are a - 3d , a - d , a + d , a + 3d , where a and d is real numbers.

According to question,

sum of all four terms = 88

(a−3d)+(a−d)+(a+d)+(a+3d)=88

4a=88

a=22 ......(1)

sum of 1st and 3rd term is 40

(a−3d)+(a+d)=40

2a−2d=40

a−d=20

from equation (1),

22−d=20

d=2

hence, a=22 and d=2

then, a−3d=22−3×2=22−6=16

a−d=22−2=20

a+d=22+2=24

a+3d=22+3×2=22+6=28

therefore, four consecutive term in an A.P are 16,20,24,28