Question

find four different solution of 2x+3y=10​

Answer 1

Answer:

Assume X= 1 and substitute in the given equation

2(1) + 3y = 10

2 + 3y = 10

3y = 10-2

3y = 8

y = 8/3

Substitute Y=8/3 in the given equation

2X + 3(8/3) = 10

2X + 8 = 10

2X = 10-8

2X = 2

X = 2/2

X = 1

Assume X= 2

2(2) + 3y = 10

4 + 3y = 10

3y = 10-4

3y = 6

y = 6/3

y = 2

Substitute y= 2 in the given equation

2X + 3(2) = 10

2X + 6 = 10

2X = 10 - 6

2X = 4

X = 4/2

X = 2

The four solutions are X= 1, Y= 8/3, X= 2, Y= 2.