find four different solutions of 2x + Y equal to 6
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1)Let, x=0
0+ 2y = 6
=> y = 3
So, ( x,y) = ( 0,3)
2) Let, y= 0
x+ 2y = 6
=> x = 6
( x,y) = ( 6, 0)
3) Let, x=2
x+ 2y = 6
=> y = 2
Hence, (x,y) = ( 2,2)
4) If, y= 1
Then, x= 4
(x,y)= (4,1)
Hope it’s helpful........ ☺
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