find four different solutions of the equation x-3y=-5
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1)x=6, y= 1/3
2)x= 1, y=4/-3
3)x=3, y=2/-3
4)x=4 ,y=1/-3
If my answer is wrong so I send you formula in the base of this formula you can solve your question
To find four solutions, we will substitute x with any real number and calculate y value:
1. when x= 1 ==> y=-3(1)-6 = -3-6=-9. Or the pair (1,-9) is a solution.
2. When x= 2 ==> y=-3(2)-6= -12. or the pair (2,-12) is a solution.
3. When x= -3 ==> y=-3(-3)-6 = 3....
4. When x= -2 ==> y=-3(-2)-6= 0\
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