Question

find four number consecutive number whose of sum is 74

Answer 1

Let the numbers are x, x+1,x+2,x+3

Sum is 74 so x+x+1+x+2+x+3=74

4x+6=74
4x=74-6
4x=68
X=68/4
X=17

Numbers are 17,18,19,20

Hope this will help u.....

Answer 2

$<i><u><p><b>$Let the numbers be x, x + 1, x + 2 and x + 3


A/q,

x + x + 1 + x + 2 + x + 3 = 74

4x + 6 = 74

4x = 74 - 6

4x = 68

x = $\frac{68}{4}$

x = 17



1st number => x = 17

2nd number => x + 1 = 17 + 1 => 18

3rd number => x + 2 = 17 + 2 => 19

4th number => x + 3 = 17 + 3 => 20


$\therefore{}$ The numbers are 17, 18, 19 and 20