Find four number in gp whose sum is 85 and product is 4096
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Answer:
1 , 4 , 16 & 64
Step-by-step explanation:
let say 4 numbers are
a ar ar^2 ar^3
sum = a (1+r + r^2 + r^3) = 85
Product = a*ar*ar^2*ar^3 = a^4r^6 = 4096
a^2r^3 = 64
if a =1 then r = 4 then numbers are 1 , 4 , 16 & 64
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