Find four numbers in A .P. such that the sum of the first and last number is 8 and the product of second and third number is 12
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let four no's be a, a+ d, a+2d, a+ 3d
a+ a+ 3d = 8
2a + 3d = 8
(a+d)( a+2d) = 12
a.a + 2da + da + 2d.d = 12
a.a,+ 3ad + 2 d.d = 12
put a= 8-3d)/2.
64 + 9 d.d - 48d)/4 + 24 -9d)/2 + 2 d.d = 12
64 + 9 d.d -48 d +,48,- 18 d + 2 d.d = 11
11 d.d - 66 d = 111
find d and in turn a
a+ a+ 3d = 8
2a + 3d = 8
(a+d)( a+2d) = 12
a.a + 2da + da + 2d.d = 12
a.a,+ 3ad + 2 d.d = 12
put a= 8-3d)/2.
64 + 9 d.d - 48d)/4 + 24 -9d)/2 + 2 d.d = 12
64 + 9 d.d -48 d +,48,- 18 d + 2 d.d = 11
11 d.d - 66 d = 111
find d and in turn a
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