Question

find four numbers in ap such that their sum of first and last term is 8 and the product of second and third term is 12
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Answer 1

The four numbers in A.P be a−3d,a−d,a+d,a+3d

Given (a−3d)+(a+3d)=8

⟹2a=8⟹a=4

Now, (a−d).(a+d)=12

⟹(4−d)(4+d)=12

⟹16−d

2

=12

⟹d

2

=4⟹d=2

Hence numbers are −2,2,6,10.

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