Question

Find four numbers in AP whose sum is 28 and the sum of whose squares is 216.
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Answer 1

Let the four numbers be (a-3d), (a-d), (a+d) & (a+3d).

Now According to question

Their sum :

(a-3d)+(a-d)+(a+d)+(a+3d)=28

4a = 28

a=7.

2.Their product

(a-3d)²+(a-d)²+(a+d)²+(a+3d)²=216

4a²+20d²=216

a² + 5d² = 54

Putting the value of a

49 + 5d² = 54

5d² = 5

d² = 1

d=±1.

Hence, the numbers are 4, 6, 8 & 10.

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Answer 2

Hi mate

The answer is attached

There is no error

hope it helps !!