Question

find four numbers is Ap whose sum is 20 and product of whose extremes is 16

Answer 1

hope you find it useful
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Answer 2

Answer:

2,4,6,8

Step-by-step explanation:

Hey there✌

Let the four numbers be a-3d,a-d,a+d,a+3d

Sum of four numbers = 20

therefore, a-3d+ a-d+ a+d+ a+3d= 20

Which implies, 4a = 20

Which is, a = 20/4 = 5

Product of extremes is 16

Which is,

(a-3d)(a+3d) = 16

a^2 - 9d^2 = 16

Which is, (since a = 5)

5^2 - 9d^2 = 16

25 - 9d^2 = 16

d^2 = 16 - 25 / -9

Which is, d = root of 1 (I don’t have the symbol of root on my iPad )

Which is, d = 1.

So, the numbers are..a-3d = 5 - 3 = 2

a-d = 5 -1 = 4

a+d = 5 + 1 = 6

a+3d = 5+ 3x1 = 8

Therefore the numbers are 2,4,6,8.

Hope this helped