Question

find four rational numbers between -3/2 and 5/3 it is a 8th std rational number question so please keep in mind and answer that way ​

Answer 1

➤ Answer :-

$\dashrightarrow \tt \frac{( - 3)}{2} \: ; \: \frac{5}{3}$

Convert them into like fractions :-

$\dashrightarrow \tt \frac{( - 3) \times 3}{2 \times 3} \: ; \: \frac{5 \times 2}{3 \times 2}$

$\dashrightarrow \tt \frac{( - 9)}{6} \: ; \: \frac{10}{6}$

Now rational numbers between them are

$\dashrightarrow \tt \boxed{ \tt \frac{( - 8)}{6} \: ; \: \frac{( - 7)}{6} \: ; \: \frac{( - 6)}{6} \: ; \: \frac{( - 5)}{6} }$

Answer 2

$\frac{-8}{6} ,\frac{-7}{6} ,\frac{1}{6} \ and\ \frac{2}{6}$ are the rational numbers between $\frac{-3}{2} \ and \ \frac{5}{3}$

Given:

Two rational numbers -3/2 and 5/3.

To Find:

Any four rational numbers between the given rational numbers.

Solution:

To find any rational numbers between the given two rational numbers, we have to make their denominator into the same number.

To make their denominator common, we will take LCM.

LCM(2,3) = 2 × 3= 6.

$\frac{-3}{2} *\frac{3}{3} = \frac{-9}{6} \\\\\frac{5}{3} *\frac{2}{2} = \frac{10}{6}$

We know that

-9<-8<-7.......<0<1<2<......<5

Dividing each term by 6

$\frac{-9}{6} < \frac{-8}{6} < \frac{-7}{6} ........0 < \frac{1}{6} < \frac{2}{6} .......\frac{10}{6}$

The rational numbers $\frac{-8}{6} ,\frac{-7}{6} ,\frac{1}{6} \ and\ \frac{2}{6}$ are between the given two rational numbers.

#SPJ3

Learn More

1)Find three rational numbers between 2/3 and 3/4

Link: https://brainly.in/question/4172138

2)Find five rational numbers between 1/2and 1/3

Link:https://brainly.in/question/1143486