Question

Find four rational numbers between 7 upon 11 and minus 4 upon 11

Answer 1

We have,

• To obtain four rational numbers between $\bf \frac{7}{11} \: \: \: \& \: \: \: \frac{ - 4}{11}$ .

We know,

• For the purpose (given above), If the denominators of fractions weren't equal, then, we would have had to make them like at first.
• But, The denominator of both fractions is similar (i.e. 11)

$\huge \dag \: \: \mathbb{ANSWER : }$

$\rm \bullet \: \:{ {1}^{st} \: \: number } = \frac{ \frac{7}{11} + \frac{ - 4}{11} }{2} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = > \frac{ \frac{7 - 4}{11} }{2} = \frac{2(7 - 4)}{11} = \frac{6}{11}$

$\rm \bullet \: \:{ {2}^{nd} \: \: number} = \frac{ \frac{6}{11} + \frac{ - 4}{11} }{2} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: = > \frac{ \frac{6 + ( - 4)}{11} }{2} = \frac{2(6 - 4)}{11} = \frac{4}{11}$

$\rm \bullet\: \: {3}^{rd} \: \: number = \frac{ \cancel{ \frac{4}{11} } + \cancel{\frac{ - 4}{11}} }{2} = \frac{0}{2} = 0$

$\rm \bullet \: \:{4}^{th} \: \: number = \frac{ - 2}{11}$

Hence,

• Required Numbers are $\boxed{\:\bf{ \frac{6}{11}, \: \frac{4}{11}, \: 0, \: and \: \frac{ - 2}{11} }\:}$