find four role of equation 4x +3y = 12
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Given equation is 4x + 3y =12
On putting x = 0 in Eq. (i), we get
4(0) +3y =12
⇒ 3y =12
⇒ y = 12 / 3 = 4
So, (0, 4) is a solution of given equation.
On putting y = 0 in Eq. (i), we get
4x+ 3 (0) =12
⇒ 4x =12
x = 12 / 4 =3
So, (3, 0) is a solution of given equation.
On putting x =1 in Eq. (i), we get
4(1) + 3y=12
⇒ 3y = 12 - 4 = 8
⇒ y = 8 / 3
So, (1,8 / 3) is another solution of the given equation.
Further, putting x = 2 in Eq. (i), we get
4(2) + 3y = 12
⇒ 3y = 12 - 8 = 4
⇒ y = 4 / 3
So, (2, 4 / 3) is also a solution of the given equation.
- Hence the four solutions of given equation are (0, 4), (3, 0), (1, 8 / 3) and (2,4 / 3).
Thank you!
@itzshivani
Answered by
0
Step-by-step explanation:
(i) Put X=0
4×(0)+3y=12
3y=12
y=12/3=4
(x,y)=0,4
(ii) put y=0
4x+3(0)=12
4x=12
x=12/4=3
(x,y)=(3,0)
(iii) put x=2
4(2)+3y=12
8+3y=12
3y=12-8=4
y=4/3
(x,y)=(2,4/3)
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