find four solution for 2(x-3)-3(y-1)=0
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2(x-3)-3(y-1) = 0
2x-6-3y+3 = 0
2x-3 -3y =0
2x-3y = 0+3
2x =3+3y
x = 3+3y/2
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solutions are :
==> if we put y = 1
then , x = 3+3(1)/2
x = 6 / 2
x = 3
so x = 3 , y = 1
==> if we put y = 3
then, x = 3+3(3)/2
x = 3+9/2
x = 12/2
x = 6
so, x= 6 ,y = 3
==> if we put y = 5
then, x = 3+3(5)/2
x = 3+15/2
x = 18/2
x = 9
so x= 9, y=5
==> if we put y = 7
then ,x = 3+3(7)/2
x = 3+21/2
x = 24/2
x = 12
so, x = 12 and y= 7
THANKS
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