Question

Find four solution for each of the following equation 2x-3(y-1) =1

Answer 1

Answer:

x+3)- 3(y-1)=0

2x+6- 3y-3 = 0 => 2x + 3y+3=0

2(x+3)- 3(y-1)=0

2x+6- 3y-3 = 0 => 2x + 3y+3=0

FOUR SOLUTIONS

1. put x= 0

2X0 + 3y-3=0

3y= 3

y= 3/3 =1

thus, (0,1) is a solution

2. put y=0

2x + 3X 0+3= 0

Step-by-step explanation:

Answer 2

Step-by-step explanation:

i don't have a idea

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