find four solution for each of the following equation 5x - 3y = 0
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5x-3y = 0
Take x = 1,5൱ - 3y = 0 ⇒ 5-3y = 0 ⇒ -3y = -5 ∴ y =
Take x = 2, 5൲ - 3y = 0 ⇒ 10 - 3y = 0 ⇒ -3y = -10 ⇒ y =
y =
Take x = 3, 5൳ - 3y = 0 ⇒ 15-3y = 0 ⇒ 3y = 15 \\\\ y = 5Take x = 4, 5൴ -3y = 0 ⇒ 20-3y = 0 ⇒ -3y = -20 ⇒ y = ∴ The four solutions of the given equation are x = 1, y = ; x = 2, y = , x = 3, y = 5 and x = 4, y = .
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