Question

find four solution of equation 3(x+4)-4(y+2)=0​

Answer 1

Answer:

$solution$

$3(x + 4) - 4(y + 2) = 0 \\ 3x + 12 - 4y - 8 = 0 \\ 3x - 4y + 4 = 0 \\ but \: take \\ x = 0and \: y = 1\: \\ lhs = 3x - 4y + 4 \\ lhs = 3(0) - 4(1) + 4 \\ lhs = 0 - 4 + 4 \\ lhs = 0 \\ the \: solution \: of \: \: the \: equation \: is \: 0 \: and \: 1.....(same \: as \: find \: all \: three)$

Answer 2

Answer:

3x-4y= -4

(0,1) , (4,4) , (8,7), (12,10)