Question

Find four solution of the linear equation y=4x+7

Answer 1

ANSWER

ANSWER(i) 4x+y=9

ANSWER(i) 4x+y=9If x=0 then

ANSWER(i) 4x+y=9If x=0 thenx×0+y=9

ANSWER(i) 4x+y=9If x=0 thenx×0+y=9⇒y=9

ANSWER(i) 4x+y=9If x=0 thenx×0+y=9⇒y=9(0,9)

ANSWER(i) 4x+y=9If x=0 thenx×0+y=9⇒y=9(0,9)(ii) 4x+y=9

ANSWER(i) 4x+y=9If x=0 thenx×0+y=9⇒y=9(0,9)(ii) 4x+y=9If y=0 then

ANSWER(i) 4x+y=9If x=0 thenx×0+y=9⇒y=9(0,9)(ii) 4x+y=9If y=0 then4x+0=9

ANSWER(i) 4x+y=9If x=0 thenx×0+y=9⇒y=9(0,9)(ii) 4x+y=9If y=0 then4x+0=9⇒4x=9

ANSWER(i) 4x+y=9If x=0 thenx×0+y=9⇒y=9(0,9)(ii) 4x+y=9If y=0 then4x+0=9⇒4x=9⇒x= 9/4

ANSWER(i) 4x+y=9If x=0 thenx×0+y=9⇒y=9(0,9)(ii) 4x+y=9If y=0 then4x+0=9⇒4x=9⇒x= 9/4 (9/4,0)

ANSWER(i) 4x+y=9If x=0 thenx×0+y=9⇒y=9(0,9)(ii) 4x+y=9If y=0 then4x+0=9⇒4x=9⇒x= 9/4 (9/4,0)(iii) 4x+y=9

ANSWER(i) 4x+y=9If x=0 thenx×0+y=9⇒y=9(0,9)(ii) 4x+y=9If y=0 then4x+0=9⇒4x=9⇒x= 9/4 (9/4,0)(iii) 4x+y=9If x=1 then

ANSWER(i) 4x+y=9If x=0 thenx×0+y=9⇒y=9(0,9)(ii) 4x+y=9If y=0 then4x+0=9⇒4x=9⇒x= 9/4 (9/4,0)(iii) 4x+y=9If x=1 then4×1+y=9

ANSWER(i) 4x+y=9If x=0 thenx×0+y=9⇒y=9(0,9)(ii) 4x+y=9If y=0 then4x+0=9⇒4x=9⇒x= 9/4 (9/4,0)(iii) 4x+y=9If x=1 then4×1+y=9⇒4+y=9

ANSWER(i) 4x+y=9If x=0 thenx×0+y=9⇒y=9(0,9)(ii) 4x+y=9If y=0 then4x+0=9⇒4x=9⇒x= 9/4 (9/4,0)(iii) 4x+y=9If x=1 then4×1+y=9⇒4+y=9⇒y=9−4=5

ANSWER(i) 4x+y=9If x=0 thenx×0+y=9⇒y=9(0,9)(ii) 4x+y=9If y=0 then4x+0=9⇒4x=9⇒x= 9/4 (9/4,0)(iii) 4x+y=9If x=1 then4×1+y=9⇒4+y=9⇒y=9−4=5(1,5)

ANSWER(i) 4x+y=9If x=0 thenx×0+y=9⇒y=9(0,9)(ii) 4x+y=9If y=0 then4x+0=9⇒4x=9⇒x= 9/4 (9/4,0)(iii) 4x+y=9If x=1 then4×1+y=9⇒4+y=9⇒y=9−4=5(1,5)(iv) 4x+y=9

ANSWER(i) 4x+y=9If x=0 thenx×0+y=9⇒y=9(0,9)(ii) 4x+y=9If y=0 then4x+0=9⇒4x=9⇒x= 9/4 (9/4,0)(iii) 4x+y=9If x=1 then4×1+y=9⇒4+y=9⇒y=9−4=5(1,5)(iv) 4x+y=9If y=1 then

ANSWER(i) 4x+y=9If x=0 thenx×0+y=9⇒y=9(0,9)(ii) 4x+y=9If y=0 then4x+0=9⇒4x=9⇒x= 9/4 (9/4,0)(iii) 4x+y=9If x=1 then4×1+y=9⇒4+y=9⇒y=9−4=5(1,5)(iv) 4x+y=9If y=1 then4x+1=9

ANSWER(i) 4x+y=9If x=0 thenx×0+y=9⇒y=9(0,9)(ii) 4x+y=9If y=0 then4x+0=9⇒4x=9⇒x= 9/4 (9/4,0)(iii) 4x+y=9If x=1 then4×1+y=9⇒4+y=9⇒y=9−4=5(1,5)(iv) 4x+y=9If y=1 then4x+1=9⇒4x=9−1=8

ANSWER(i) 4x+y=9If x=0 thenx×0+y=9⇒y=9(0,9)(ii) 4x+y=9If y=0 then4x+0=9⇒4x=9⇒x= 9/4 (9/4,0)(iii) 4x+y=9If x=1 then4×1+y=9⇒4+y=9⇒y=9−4=5(1,5)(iv) 4x+y=9If y=1 then4x+1=9⇒4x=9−1=8⇒x=2

ANSWER(i) 4x+y=9If x=0 thenx×0+y=9⇒y=9(0,9)(ii) 4x+y=9If y=0 then4x+0=9⇒4x=9⇒x= 9/4 (9/4,0)(iii) 4x+y=9If x=1 then4×1+y=9⇒4+y=9⇒y=9−4=5(1,5)(iv) 4x+y=9If y=1 then4x+1=9⇒4x=9−1=8⇒x=2(2,1)