Question

find four solutions of the linear equation 2 (x+3) - 3(y-1) = 0

Answer 1

hey buddy ! u think this is only your answer....

2(x+3)- 3(y-1)=0

2x+6- 3y-3 = 0 => 2x + 3y+3=0

2(x+3)- 3(y-1)=0

2x+6- 3y-3 = 0 => 2x + 3y+3=0

FOUR SOLUTIONS

1. put x= 0

2X0 + 3y-3=0

3y= 3

y= 3/3 =1

thus, (0,1) is a solution

2. put y=0

2x + 3X 0+3= 0



hope it helps you... plz mark as brainliest...

Answer 2

2x+6-3y-3is equal to 0
2x-3yis equal to 0-6+3
x equal to 3